No clue on this one?

Question

One number is 8 more than another. If the sum of the smaller
number and twice the larger number is 46, find the two numbers.

Answer 1

a. x > smaller number
b. y > larger number

1) y = x+8
2) x + 2y = 46

First: substitute "x+8" with "y" in the 2nd equation.

2) x + 2(x+8) = 46
x+2(x)+2(8) = 46
x+2x+16 = 46
3x+16 = 46

Sec: combine "like" terms - subtract 16 from both sides (when you move a term to the opposite side, always use the opposite sign).

3x+16-16 = 46-16
3x = 46-16
3x = 30 (Divide both sides by 3).
3x/3 = 30/3
x = 30/3
x = 10

Third: substitute 10 with "x" in the 1st equation.

1) y = x+8
y = 10+8
y = 18

a. x = 10
b.y = 18

Answer 2

Let x be the smaller of the two numbers.
Then the other number is x+8

We know the sum of the smaller number and twice the larger number is 46.
x + 2*(x+8) = 46

Then just use algebra:
x + 2x + 16 = 46
3x = 46 - 16
3x = 30
x = 10

The smaller number is 10
The larger number is 10+8 = 18.

Hope that helps!

Answer 3

Let x = first number
then x + 8 = 2nd number

x + 2(x + 8) = 46

3x = 30

x = 10 smaller number
x + 8 = 18 larger number
.

Answer 4

small num =x
larger num =x+8
sum of the smaller number and twice the larger number is 46
x+[2(x+8)]=46
3x+16=46
3x=30 x=10
so small num = 10, larger num =18

Answer 5

let x be the smaller, y the larger:

x + 8 = y
x + 2y = 46

plug in for y:
x + 2(x+8) = 46
x = 48/3

so y = 48/3 + 8 = 72/3

Answer 6

small number is 10 large number is 18.

10+18+18=46

Hope this helps. THis took me about 8 mins. haha. God Bless

Answer 7

x+2(x+8)=46

x+2x+16=46

3x=30

x=10

so.... 10 and 18

Answer 8

x = y + 8
2x + y = 46

2y + 16 + y = 46
3y = 30

y = 10
x = 18