Chemistry Problem?

0 ⤊

Reduce the following complete equations to net ionic form:
a. 6Cr(NO3)2 + 3CuSO4 ---> 3Cu + 4Cr(NO3)3 + Cr2(SO4)3
b. H2SO4 ---> H20 + SO3
c. P4 O10 + 6 H20 ---> 4H3PO4
d. 4CuCNS + 7KlO3 + 14HCl ---> 4HCN + 4CuSO4 + 7ICI + 7KCl+5H20

2007-05-30 11:55:01 · 2 answers · asked by San Fran Kid 2 in Science & Mathematics ➔ Chemistry

2 answers

These are basically all the same. Just break them up into ions and use the coefficients

For example, your first problem would start with

6 Cr+2 and 2 (NO3) -1, etc.

2007-05-30 12:22:23 · answer #1 · answered by reb1240 7 · 0⤊ 0⤋

looks very complicated

2007-05-30 18:58:46 · answer #2 · answered by Bobbay! 2 · 0⤊ 0⤋