what is (4u + 7v)^2
2007-05-30 11:26:18 · 6 answers · asked by **Lilyanne** 3 in Science & Mathematics ➔ Mathematics
how about this?
(y-7)^2
and
(2x-6)^2
and
(5+8)^2
2007-05-30 11:57:02 · update #1
to solve this, you should use the FOIL method. FOIL stands for "first, inner, outer, last" in this method you expand out the equation to (4u+7v) * (4u+7v). then you multiply the first terms to get 16u^2, the outer terms equal 28uv, the inner terms also equal 28uv, and the last terms equal 49v^2. this equals 16u^2+56uv+49v^2. Hope this helps!
2007-05-30 11:35:32 · answer #1 · answered by DXFlounder 2 · 0⤊ 0⤋
16u^2 + 22uv + 49v^2
2007-05-30 18:32:14 · answer #2 · answered by Anonymous · 0⤊ 0⤋
(4u + 7v)^2
16u² + 56uv + 49v²
2007-05-30 18:32:50 · answer #3 · answered by Robert L 7 · 0⤊ 0⤋
(4u-7v)^2=16u^2-56uv+49v^2
2007-05-30 18:32:46 · answer #4 · answered by Anonymous · 0⤊ 0⤋
16u^2+56uv+49v^2
2007-05-30 18:37:02 · answer #5 · answered by tania N 1 · 0⤊ 0⤋
16u^2+56vu+49v^2
2007-05-30 18:32:43 · answer #6 · answered by Anonymous · 0⤊ 0⤋