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Can you solve this equation? 4x + 6y=2876. x + y=525. What are x and y?

2007-05-30 10:32:26 · 7 answers · asked by Anonymous in Science & Mathematics Mathematics

7 answers

y = 388
x = 137

Multiply the second equation by 4 to give you 4x + 4y = 2100

Subtract this from the first equation to give you 2y = 776 and halve both sides to give you y = 388

Substitute in the second equation to give you x + 388 = 525 and x is therefore = 137.

2007-05-30 10:45:28 · answer #1 · answered by Anonymous · 0 2

Series of two equations.

4x+6y = 2876
x+ y = 525
--------------------

Mulitply both sides of the bottom by 4

4x + 6y = 2876
4 (x + y) = 4(525) ==> 4x+4y =2100

4x + 6y = 2876
- (4x + 4y) = 2100
--------------------------
2y = 776 ==> y=388

Plug the value for y into either of the first two equations, I'll pick x+y = 525

x + 388 = 525 ==> x = 137

Test on other equation (4x + 6y = 2876)

4(137) + 6 (388) ==> 548 + 2328 = 2876 (check)

2007-05-30 10:44:31 · answer #2 · answered by Anonymous · 0 0

*Solve for "x" or "y" in either equation. Let's solve for "x" in the 2nd equation.

1) 4x + 6y = 2876
2) x + y = 525

First: isolate "x" on one side (left) - subtract "y" from both sides (when you move a term to the opposite side, always use the opposite sign).

x + y-y = 525-y
x = 525-y

Sec: replace/substitute "525-y" with "x" in the 1st equation.

4(525-y) + 6y=2876
4(525)+4(-y)+6y = 2876
2100-4y+6y = 2876
2100+2y = 2876 (*Subtract 2100 from both sides).
2100-2100+2y = 2876-2100
2y = 2876-2100
2y = 776 (*Divide both sides by 2).
2y/2 = 776/2
y = 776/2
y = 388

Third: replace 388 with "y" in the 2nd equation.

x + 388 = 525 (*Subtract 388 from both sides).
x + 388-388 = 525-388
x = 525-388
x = 137

Solution set: (137, 388)

2007-05-30 11:07:08 · answer #3 · answered by ♪♥Annie♥♪ 6 · 0 0

Using the second equation and solving for X we get:
x = 525-y
Substitute this value for x in the first equation:
4(525-y) +6y = 2876
Multiply the terms getting:
2100 -4y +6y = 2876
Collect terms:
2100 +2y = 2876
Subtract 2100 from both sides getting:
2y = 776
Divide both sides by 2:
y = 388
Using the second equation:
x = 525 - 388 or
x = 137
Substitute the two values back into the equations as a check...

2007-05-30 10:42:26 · answer #4 · answered by BAM55 4 · 0 0

eqn#2 x= -y+525 (3)
sub in eq#1 4(-y+525) +6y =2876
2y+2100 = 2876
2y = 776
y = 388
sub in eqn#3 x= -388+525
x= 137

2007-05-30 10:40:32 · answer #5 · answered by Anonymous · 0 0

4x + 6y = 2876
x + y = 525 | Origional Problem

4x+6y = 2876
-4x - 4y = -2100 | Multiplied bottom equation by negative 4

2y = 776 | Added equations together.

y = 388

x + (388) = 525 | Pluged y into origional equation
x = 137

2007-05-30 10:39:34 · answer #6 · answered by chess19902000 2 · 0 0

4x + 6y = 2,876
x + y = 525
4x + 4y = 2,100
2y = 776
y = 388
x = 525 - 388 = 137

2007-05-30 10:42:29 · answer #7 · answered by Helmut 7 · 0 0

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