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I think that I might have this but want to make sure. The ? is:
Determine graphically the vertices of the triangle, the equation of whose sides are given as y=x, y=0, 2x + 3y=10. Interpret the results.
For y=x, am I suppose to plot a point at the corner or 0 of y and x and so on? Thanks!

2007-05-30 10:18:05 · 1 answers · asked by krisy 1 in Science & Mathematics Mathematics

1 answers

"y=x" is a diagonal line through the origin, (1,1), (2,2), (3,3), etc. (Note that in all those points, y=x. You can plot a couple of those points and use a ruler to draw the line.)

y=0 is the x-axis. Obviously, it intersects the diagonal line at the origin (y=0 and y=x, thus x=0 as well).

2x + 3y = 10 intersects the other two lines to form a triangle in the positive-x, positive-y quadrant. It intersects the x-axis at (5,0), and the y=x line at (2,2)

So, your three vertices are: (0,0), (5,0), (2,2)

2007-05-30 10:24:00 · answer #1 · answered by McFate 7 · 0 0

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