C*10^n has n zeros when it is written in decimal form
2007-05-30 09:08:07 · 5 answers · asked by brunette12x 1 in Science & Mathematics ➔ Mathematics
If C is an integer, it's true.
If C is not an integer (has a decimal), it's not true.
10^1 = 10
5*10^1 = 50 - one zero.
10^2 = 100
5.3*10^2 = 530 - one zero
6.32 * 10^2 = 632 - zero zeros.
2007-05-30 09:19:10 · answer #1 · answered by Dave B. 4 · 0⤊ 2⤋
I could see more or less than n zeros.
More one way: C=1000, n=3
C*10^n = 1000*10^3 = 1,000,000
That doesn't have n (three) zeros, it has six.
More another way: C=1001, n=2
C*10^n = 1001*10^2 = 100,100
That doesn't have n (two) zeros, it has four. (The statement says "has" zeros, not "ends with" zeros.)
Less: C=3.141, n=5
C*10^n = 3.141*10^5 = 314,100
That doesn't have n (five) zeros, it has two.
Less another way: C=0, n=100
C*10^n = 0*10^100 = 0
That doesn't have n (100) zeros, it has one.
The way to correct that statement would be: "C*10^n ENDS WITH AT LEAST n zeros when C is A NONZERO INTEGER."
2007-05-30 16:10:47 · answer #2 · answered by McFate 7 · 3⤊ 0⤋
If C=10, the statement is never true for any n.
2007-05-30 16:12:58 · answer #3 · answered by Anonymous · 0⤊ 0⤋
what if c=0? what if n=0?
2007-05-30 16:11:05 · answer #4 · answered by J Z 4 · 0⤊ 0⤋
Because "C" might have plenty of zeros already. For instance, C = 20,000.
2007-05-30 16:11:13 · answer #5 · answered by Mike T 2 · 0⤊ 0⤋