how do i simplify this exuation with no negative exponents.
(x^3)^-4
------------(((division line thingy)))
xy^-7z^5
2007-05-30 08:08:29 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
how do i simplify this expresion with no negative exponents.
(x^3)^-4
------------(((division line thingy)))
xy^-7z^5
2007-05-30 08:09:38 · update #1
= x^-12y^7 / xz^5
= (y^7) / (x^13*z^5)
Basically just simplify as much as you can, and bring the exponent with a base down, or up, and make it positive.
E.g.
3^-5
The exponent is not in its proper position (because it is negative) so we must bring it down and make it positive.
1/3^5
= 1/243
Lets break this problem down.
First, simplify the numerator. You have (x^3)^-4. Using exponent laws, you can change that to x^-12.
Look at the denominator now. You have xy^-7*z^5. Nothing can really be done with that, so lets see what we can move.
= x^-12y^7 / xz^5 -- (took the y^-7 from the bottom, and put it on top)
= (y^7) / (x^13*z^5) (took the x^-12 from the top, bring it to the bottom, use exponent laws and make it positive).
Good luck.
2007-05-30 08:11:53 · answer #1 · answered by de4th 4 · 0⤊ 0⤋
x^-13/y^-7z^5
2007-05-30 15:23:07 · answer #2 · answered by Yauheniya D 1 · 0⤊ 0⤋
just change the numerator and denominator around because both have negative sign in it and then solve it
2007-05-30 15:14:59 · answer #3 · answered by Anonymous · 0⤊ 0⤋
= (x³)^(-4) / (x.y^(-7).z^5)
= x^(-12).y^(7) / (x.z^5)
= y^7 / (x^13.z^5)
2007-05-31 04:36:54 · answer #4 · answered by Como 7 · 0⤊ 0⤋