A small company produces both bouquets and wreaths of dried flowers. The bouquets take 1 hour of labor to produce, and the wreaths take 2 hours. The labor available is limited to 80 hours per week, and the total production capacity is 60 items per week. Write a system of inequalities representing this situation, where x is the number of bouquets and y is the number of wreaths. Then graph the system of inequalities.
2007-05-30 07:46:55 · 3 answers · asked by lois g 2 in Science & Mathematics ➔ Mathematics
labor: 1x + 2y ≤ 80
count: x + y ≤ 60
to graph 1st inequality, draw a line from x intercept at 80 to y intercept at 40. likewise from x intercept 60 to y intercept 60 for 2nd. shade the polygon enclosed by these lines and the x and y axes. It will have corners at (0,0), (0,40), (40,20), and (60,0).
2007-05-30 08:05:16 · answer #1 · answered by Philo 7 · 0⤊ 0⤋
The guy at the top is right.
2007-05-30 14:54:59 · answer #2 · answered by Kristina 3 · 0⤊ 0⤋
x+2y<=80
x+y<=60
graphing these is easy
2007-05-30 14:52:12 · answer #3 · answered by sreenidhi.a_85 2 · 0⤊ 0⤋