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Nitric oxide is made from the oxidation of ammonia. How many moles of nitric oxide can be made from the reaction of 3.80 mol NH3 with 5.15 mol O2?

4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(g)

a.4.12 mol
b.6.44 mol
c.5.15 mol
d.8.95 mol
e.3.80 mol

2007-05-30 07:14:46 · 2 answers · asked by Anonymous in Science & Mathematics Chemistry

2 answers

e.3.80 mol

2007-05-30 07:27:00 · answer #1 · answered by abd elmoniem m 2 · 0 0

First find the limiting reactant. What will run out first: NH3 or O2.

3.80molNH3 x 5molO2/4molNH3 = 4.75molO2.

So you need 4.75 moles O2 to react with 3.80 moles NH3. You have 5.15 moles O2, more than enough. So NH3 is the limiting reactant. Go with that.

3.80molNH3 x 4molNO/4molNH3 = 3.80mol NO

2007-05-30 07:31:34 · answer #2 · answered by steve_geo1 7 · 1 0

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