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The complete combustion of 0.40 moles of butane gas, C4H10, will

a.consume 5.2 mol O2 and produce 3.2 mol CO2.
b.consume 0.40 mol O2 and produce 0.20 mol CO2.
c.consume 2.6 mol O2 and produce 1.6 mol CO2.
d.consume 1.3 mol O2 and produce 0.80 mol CO2.
e.consume 0.80 mol O2 and produce 0.40 mol CO2.

2007-05-30 05:40:21 · 1 answers · asked by kallystarr 1 in Science & Mathematics Chemistry

1 answers

2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O

c.consume 2.6 mol O2 and produce 1.6 mol CO2.

2007-05-30 05:47:05 · answer #1 · answered by ag_iitkgp 7 · 0 0

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