How many moles of potassium bromide can be produced from the reaction of 2.92 moles of potassium with 1.78 moles of bromine gas?
2 K(s) + Br2(g) → 2 KBr(s)
a.3.56 mol
b.5.84 mol
c.1.78 mol
d.1.46 mol
e.2.92 mol
is the answer e?
thanks
2007-05-30 05:27:58 · 5 answers · asked by kallystarr 1 in Science & Mathematics ➔ Chemistry
yes, the answer is e
2007-05-30 05:31:30 · answer #1 · answered by Anonymous · 0⤊ 0⤋
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not gh3y
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Yes. The answer is "e"
All the bromine gas won't be reacted, since 2.92 mol K will only react with (2.92 / 2) 1.46 mol of Br2 before being exhausted.
Since 2 mol KBr are produced for every 2 mol K reacted, 2.92 mol K will produce 2.92 mol KBr
2007-06-03 04:16:34 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Yes. The answer is "e"
All the bromine gas won't be reacted, since 2.92 mol K will only react with (2.92 / 2) 1.46 mol of Br2 before being exhausted.
Since 2 mol KBr are produced for every 2 mol K reacted, 2.92 mol K will produce 2.92 mol KBr
2007-05-30 05:30:34 · answer #3 · answered by not gh3y 3 · 0⤊ 0⤋
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2016-05-17 00:47:55 · answer #4 · answered by Michelle 4 · 0⤊ 0⤋
Yes its e.
2007-05-30 05:34:54 · answer #5 · answered by ag_iitkgp 7 · 0⤊ 0⤋