If 2x2 - 14x + 12 represents the area of a rectangle, what is the perimeter of that rectangle?
A) 6x - 12
B) 4x - 16
C) 3x - 8
D) 6x - 16
2007-05-30 04:59:34 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
2x² - 14x + 12 = (2x-2)(x-6)
Area = Length * Width
Perimeter = Length + Length + Width + Width
(2x - 2) + (2x - 2) + (x -6) + (x-6) = 6x -16
D) 6x - 16
2007-05-30 05:05:54 · answer #1 · answered by Anonymous · 1⤊ 0⤋
I'll show you how to find the answer: First, notice that the expression 2x^2-14x+12 is quadratic by virtue of the highest power being two. Secondly notice that you can easily factor out a two giving you: 2(x^2-7x+6). Notice that the quadratic expression inside the paranthesis is easily factorable. Factor the expression, and redistribute the two and you'll obtain the length and width of the rectangle because
area=(length)(width). Then all you need to do is calculate the perimeter by adding twice the length to twice the width. Good Luck.
2007-05-30 12:16:02 · answer #2 · answered by Anonymous · 0⤊ 0⤋
ab=2x^2-14x+12
ab= (x-6)(2x-2)
a=x-6
b=2x-2
2(a+b) =2( (x-6)+(2x-2) )
=2(3x-8)
=6x-16
2007-05-30 12:20:06 · answer #3 · answered by iyiogrenci 6 · 0⤊ 0⤋