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Let f(x) = 5(2 - x)/(x – 3)^3. Determine the coordinates of the x and y-intercepts.

a) [0, -(10/27)], (2, 0)
b) (0, 3) (2, 0)
c) no x- or y- intercepts
d) (3, 0), [0, -(10/27)]

2007-05-30 03:47:15 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

Hmmmm......
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2007-05-30 13:01:25 · answer #1 · answered by Anonymous · 0 0

Answer: a) [0, -(10/27)], (2, 0)


x-intercept (x,0)
x=2



y-intercept (0,y)
f(0)=-10/27

2007-05-30 03:54:27 · answer #2 · answered by iyiogrenci 6 · 0 0

y = 5(2-x) /(x-3)^3

if you want to get y intercept ,put x=0

y = 5(2-0)/(0-3)^3 = -10/27
so,the point is (x,y)=(0,-10/27)
-----------------------------------------------
to get x-intercept,put y=0

0 = 5(2-x) /(x-3)^3
0 * (x-3)^3 = 5(2-x)
0 =5(2-x)
0/5 =5(2-x)/5
0=2-x
2=x
so the point is (2,0)
------------------------------------
so the answer is a)[0, -(10/27)], (2, 0)

2007-05-30 04:19:56 · answer #3 · answered by function i 1 · 0 0

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