2007-05-30 01:47:47 · 9 answers · asked by wick4d_on4 1 in Science & Mathematics ➔ Mathematics
midpoint formula
x₁+ x₂/ 2 , y₁+ y₂/ 2
3 - 3 / 2 , - 4 + 4 / 2 =
0 / 2 , 0 / 2
Midpoint is (0, 0)
- - - - - - - - -s-
2007-05-30 02:20:41 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
[3 + (-3)]/2 = 0/2 = 0
(-4 + 4)/2 = 0/2 = 0
The answer is (0, 0)
2007-05-30 08:50:29 · answer #2 · answered by Amit Y 5 · 0⤊ 0⤋
The formula is ((x1+x2)/2 , (y1+y2)/2)
Therefore, ((3+-3)/2 , (-4+4)/2)
Result: (0/2 , 0/2) = (0,0)
2007-05-30 08:52:22 · answer #3 · answered by nivik 3 · 0⤊ 0⤋
(0, 0)
xm = (3 + -3)/2 = 0
ym = (-4 + 4)/2 = 0
2007-05-30 08:50:06 · answer #4 · answered by michael_scoffield 3 · 0⤊ 0⤋
The answer is (0,0). Here's a progam you can put into your graphing calculator(if you have one).
Go to PRGM
Go to NEW
Give it a name and then type the following, each on a new line
Prompt A,B,C,D,
((A+C)/2) (STOR(button above the ON))E
((B+D)/2) (STOR(button above the ON))F
Disp(Press PRGM, then go to I/O. Press #3)
Press 2nd MODE and you're done.
2007-05-30 09:25:43 · answer #5 · answered by michaelbatorski 1 · 0⤊ 0⤋
(0,0) maybe....try drawing it on a graph and draw a line connecting the 2 and see where the midpoint lies.
2007-05-30 09:01:02 · answer #6 · answered by Jon M 3 · 0⤊ 0⤋
mid point M ((3 + (- 3) ) / 2, (- 4 + 4)/2)
M(0,0) is mid point.
2007-05-31 08:13:27 · answer #7 · answered by Como 7 · 0⤊ 0⤋
x = (x_1 + x_2)/2
x = (3+-3)/2
x=0
y = (y_1 + y_2)/2
y = (-4 + 4)/2
y = 0
(0,0)
2007-05-30 08:50:41 · answer #8 · answered by Anonymous · 1⤊ 0⤋
(0,0)
2007-05-30 08:49:38 · answer #9 · answered by farhad n 2 · 0⤊ 0⤋