2007-05-30 01:45:08 · 9 answers · asked by wick4d_on4 1 in Science & Mathematics ➔ Mathematics
The average of 2 and 2 is 2. The average of 2 and 4 is 3. So the coordinates are (2,3).
2007-05-30 01:48:20 · answer #1 · answered by Rale Baskinson 3 · 0⤊ 0⤋
The formula for locating the midpoint is as follows: M = {[(x1 + x2)/2] , [(y1 + y2)/2]} So enable (x1, y1)= (2, -3) and enable (x2, y2)= (4, 2) So M = {[(2 + 4)/2] , [(-3 + 2)/2]} M = {3, -a million/2}
2016-12-30 07:00:02 · answer #2 · answered by grimwood 3 · 0⤊ 0⤋
Take the average of the vectors by adding them and dividing by 2:
((2 + 2)/2, (2 + 4)/2) = (4/2, 6/2) = (2, 3)
2007-05-30 01:49:04 · answer #3 · answered by Amit Y 5 · 0⤊ 0⤋
The formula is ((x1+x2)/2 , (y1+y2)/2)
Therefore, ((2+2)/2 , (2+4)/2)
Result: (4/2 , 6/2) = (2,3)
2007-05-30 01:50:06 · answer #4 · answered by nivik 3 · 0⤊ 0⤋
it's (2+2)/2, (2+4)/2
=4/2, 6/2
=2,3
2007-05-30 01:49:33 · answer #5 · answered by heythere 3 · 0⤊ 0⤋
xm = (x1 + x2)/2 = (2 + 2)/2 = 2
ym = (y1 + y2)/2 = (2 + 4)/2 = 3
(2,3)
2007-05-30 01:49:23 · answer #6 · answered by michael_scoffield 3 · 0⤊ 0⤋
((2 + 2)/2,(2 + 4)/2) = (2,3)
Mid point is (2,3)
2007-05-30 01:49:38 · answer #7 · answered by Como 7 · 0⤊ 0⤋
please... fork over your entire assignment. I could use the practice. Please... stay as stupid as possible for as long as possible. I could seriously use the reduced competition in my own professional future
2007-05-30 01:56:41 · answer #8 · answered by Anonymous · 0⤊ 0⤋
(2,3)
2007-05-30 01:47:40 · answer #9 · answered by farhad n 2 · 0⤊ 0⤋