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Answer this question for a top secret about reality:

An airplane flies in the wind direction at 140 mph and against the wind at 110 mph. Find the speed of the airplane in still air.

Hints: Here are four answers, which one is it?
110 mph
120 mph
125 mph
or
140 mph

2007-05-28 22:14:37 · 7 answers · asked by Angel_Wolf 2 in Science & Mathematics Mathematics

7 answers

Let me denote by P the speed of the plane in still air and by W the wind speed.

The first clause gives us: P + W = 140
(P and W have same sign, assumed positive, because they are in the same direction).

Similarly, the second clause gives us P - W = 110.

Adding the two equations, we get:
2P = 250 => P = 125.

Hence the correct answer is the third answer in the list, 125mph.

2007-05-28 22:24:49 · answer #1 · answered by Neil J 2 · 2 1

the previous answer tat plane can fly only with or against the wind is false.

planes can fly in still air. but it cannot fly without air.

since the plane flies in the wind direction at 140 mph and against the wind at 110 mph.
speed of the plane is between 140 and 110.
asuming that the wind speed is same when it blow atainst and in the direction of the plane the speed of the plane will be the average of these 2 values which wil be
125

2007-05-29 05:27:04 · answer #2 · answered by rana_22_m 2 · 1 1

125 mph. Sum of two speeds divided by 2.
Let x be the speed of plane in still air & y be of wind.
x+y =140
x-y=110
add both the equations
2x = 250
x=125 mph

2007-05-29 05:25:12 · answer #3 · answered by Jain 4 · 1 1

x+y=140
x-y=110 Add them together
2x = 250
x = 125 (The aircraft speed in still air, rather than the 15 mph wind it is flying through.

The secret to life is that there --is-- no secret to life ☺

Doug

2007-05-29 05:26:56 · answer #4 · answered by doug_donaghue 7 · 0 2

140 but it's going to have to use more welly to maintain it against a 110 headwind than if there was no wind.

2007-05-29 05:19:59 · answer #5 · answered by Anonymous · 0 2

The answer would be 0mph, since a plane can only travel either with or against the wind currents, but not independent of them.

2007-05-29 05:22:34 · answer #6 · answered by teknomancer73 4 · 0 2

Add the two speeds together and divide by two.

2007-05-29 05:21:37 · answer #7 · answered by Pete 2 · 0 2

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