Thanks for all your answers..but I am still having trouble with the problem below..any help will beappreciated

Question

Solve using the quadratic

0.04x^2 - 0.04x + 0.07 =0

Answer 1

I would start by multiplying both sides by 100 to get:
4x^2+4x+7=0 using the quadratic equation
[-4+-sqrt(16-112)]/8

Answer 2

I can discern that you are being misled by the decimal points.
Hint:
Always convert your equation to whole numbers.
Here is your equation to solve:
Multiple both sides of the equation by 100 to get rid of the decimal points.
Then you get the following:
4x^2 - 4x + 7 = 0
This is now a form of:
a^2 -bx + c = 0
Because you can not use factoring due to (c = 7), which is not a perfect square of any two numbers, use the quadratic formula:
-b+/-{[(b^2 - 4ac)^1/2]}/2a
(In words: the root is minus b plus or minus (the square root of b squared minus 4 times a times c) divided by 2 times a).
You have to simplify the expression b squared minus 4ac first and then divided the result by 2a. Finally add or subtract the value from minus b.
Hence:
Substitute the values of a, b, and c.
You will obtain 2 roots.
Consult your textbook for examples.
If you still have any difficulties substituting, email me and I will give you the solution step by step.
Good Luck!

Answer 3

If multipied by 100:
4x^2 - 4x + 7 = 0,
then solve by any method.

in this case by completing the square...

4x^2 - 4x = -7
x^2 - x = -7/4

x^2 -x + 1/4 = -7/4 + 1/4 = -6/4

(x - 1/2)^2 = -6/4...x - 1/2 = + or - (i * sqrt 6) / 2

the answer is: x = (1 + i * sqrt 6)/2 and (1 - i * sqrt 6)/2.

the end. (the roots are imaginary)

Answer 4

Anybody would. But, here is a hint. Multiply the whole mess by 100. Find the roots of that equation and divide by 10 to get the answer to this equation.

Answer 5

use the quadratic formula and first check the square root of (b^2-4ac)= square root of (-0.096) which is negative no real solution(root) if is negative root that's call imaginary number inside the root

If root is not negative can continue with the quadratic formula
(-b+/- sqr(b^2-4ac))/2a