Long division polynomial?

Question

how do you divide x^2/2x + 4 ?
can you explain step by step.

Answer 1

½x - 1 R 4

Set it up like the long division you learned for numbers with x^2 + 0x + 0 under the division bar. Then put whatever you have to multiply the "2x" in 2x + 4 by to get 1x^2: ½x. Do the multiplication placing terms under the x^2... in their proper places: you then have (x^2 + 0x) - (x^2 + 2x) = -2x. Put the "-2x" under the x column and then put above the 0 the number you have to multiply the "2x" in 2x + 4 by to get -2x: -1. Do the multiplication and subtraction: you get 4. You stop when you reach the x^0 term (4x^0 = 4). Anything left (number only) is the remainder. So your answer is: ½x - 1 R 4.

Answer 2

I dunno how to do your exact problem, to be honest. I CAN do an example of polynomial long division for you, though! I hope it helps a little, but if it doesn't, sorry!

2x^2/(x+4)
----------------------_____
Write it as x+4 | 2x^2

x times WHAT is 2x^2?
x times 2x is 2x^2!!

So the first part of the answer is 2x. Write that down in the appropriate space in the equation above.

Times the 2x we just found to each part of x+4 and write it down below the original equation. It should look sorta like this by now:


2x
------ _____
x+4 | 2x^2
2x^2 + 8x

Add is a minus sign to the left of the "2x^2 + 8x". Then subtract!

You are left with -8x. Since there is nothing left, this is called a remainder.

The final answer is 2x R: -8x.