2(x-7) - 5 = 5 - (3 -2x)
2x-14-5 = 5- 3 +2x
2x-19 = 2 + 2x
2x = 21 + 2x
If I keep going there will be no solution for x. the x will be eliminated. Right?
2007-05-28 12:24:26 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
You are absolutly correct! x has NO SOLUTION. If you were to plot the lines on an x and y axis, they would be parallel!
2007-05-28 12:31:37 · answer #1 · answered by A confused bio student 2 · 0⤊ 0⤋
2(x-7) - 5 = 5 - (3 -2x)
2x-14-5=5-3+2x
2x-19=2x+2
-19=2
this problem doesn't have a solution since, as you found, the variables cancel out leaving you with unequal constants.
Your teacher INTENDED for you to get confused. Teachers can be like that.
2007-05-28 19:38:10 · answer #2 · answered by yupchagee 7 · 0⤊ 0⤋
Correct. The fact that you get a falsehood like 0 = 21 means that this equation cannot be made true no matter what you put in for x. This equation has no solution, as sometimes happens in algebra problems.
Another possibility might occur if your variable cancels out and you get something that is always true, like 0 = 0. In that case, any value you put in for x will work and your equation has an infinite number of solutions. This is an equation of this second sort:
2(x - 7) - 5 = 1 - 2(10 - x)
2007-05-28 19:39:42 · answer #3 · answered by devilsadvocate1728 6 · 0⤊ 0⤋
2(x - 7) - 5 = 5 - (3 - 2x)
2x - 14 - 5 = 5 - 3 + 2x
2x - 19 = 2 + 2x
-19 = 2
Yes, there is no solution. Don't doubt yourself.
2007-05-28 19:28:50 · answer #4 · answered by its_victoria08 6 · 0⤊ 0⤋
there is a solution:
2x - 14 - 5 = 5 - 3 - 2x
2x - 19 = 2 - 2x
4x - 19 = 2
4x = 21
x = 5 and a 1/4
2007-05-28 19:34:21 · answer #5 · answered by Anonymous · 0⤊ 1⤋
That's right. There is no value of x that could possibly make this equation true, since if there was, then per the reasoning above, that would cause 0=21, which is certainly not true.
Conversely, if in the course of solving equations you end up with something like 0=0, then every number will solve the equation (assuming all your algebraic manipulations are invertible -- obviously, obtaining 0=0 by multiplying both sides by 0 tells you absolutely nothing about what numbers solve the equation).
2007-05-28 19:30:29 · answer #6 · answered by Pascal 7 · 0⤊ 0⤋
You're absolutely correct.
Actually, if you follow the logic to the next step, you bet 0 = 21. Now either you have revolutionized mathematics, of there's an error in the problem.
I have little doubt that you've checked to make sure you've copied it out of the text correctly. Mistakes get into math textbooks all the time. People with Ph.D.s are forced to publish. So they whip out math textbooks. proofreaders are pretty good about spelling and syntax, but they usually don't know math. So mistakes get in.
Good work.
2007-05-28 19:41:36 · answer #7 · answered by gugliamo00 7 · 0⤊ 0⤋
There is no solution because 0x=21 x=21/0 is undefined
2007-05-28 19:29:54 · answer #8 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
Your analysis is correct. Regardless of what value you choose for x, it will not satisfy the equation. (Reason: 21 is not equal to 0, so the right member of the equation will always be larger than the left member.)
2007-05-28 19:30:36 · answer #9 · answered by actuator 5 · 0⤊ 0⤋
You are so right! There is no solution for this equation; it's an impossible situation.
2007-05-28 19:28:54 · answer #10 · answered by TitoBob 7 · 0⤊ 0⤋