math problem help?

Question

peter walked at a rate of 4 miles in 50 minutes. Jan walked at a rate of 3 miles in 30 minutes. Which statement correctly describes this situation?

a. Jan's walking rate was 0.18 mile per minute faster than peter's.

b. jan's walking rate was 0.18 mile per minute slower than peter's.

c. Peter's walking rate was 0.02 mile per minute faster than Jan's

d. peter's walking rate was 0.02 mile per minute slower than Jan's.

Answer 1

We must calculate each person's rate using
we know d = r*t ===> rate = dist / time

Peter = 4 miles / 50 minutes = 2/25 miles per minute
===> change to decimal 0.08 miles per min
Jan = 3 mies / 30 minutes = 1/10 mile per minute = 0.1

Peter is 0.02 SLOWER than Jan

(d) is CORRECT answer


=]

Answer 2

Peter: 4 miles / 50 minutes = .08 miles/minute

Jan: 3 miles/ 30 minutes = .10 miles/minutes

.10 - .08 = .02

so d) Peter's walking rate was 0.02 mile per minute slower than Jan's.

Answer 3

The correct answer is D.

This is how I solved it:
First I simplified to miles per minute.
Peter walks at 4 miles per 50 minutes, or 4 miles per 50/60 hours. Simplifying, this gets us:
4 / (50/60) or 4 * 60 / 50. (Dividing by a fraction is multiplying by the reciprocal of the fraction)
4 * 60 = 240 / 50, or 24/5, which is 4.8 miles per hour.
Jan walks at 3 miles per 30 minutes, or 4 miles per 30/60 hours. Simplifying, this gets us:
3 / (30/60) or 3 * 60 / 30.
3 * 60 = 180 / 30, or 18/3, which is 6 miles per hour.
So, Jan is walking faster at a rate of 1.2 miles per hour (6-4.8).

However, the answers are asking for a value in miles per minute, so we have to divide the miles per hour by 60.
1.2 / 60 = .02.

Since Jan is walking faster, C cannot be correct.

D is the correct choice.

Answer 4

peter walked at a rate of 4 miles in 50 minutes.

Thus Peter's walking rate = 4/50 = 0.08 miles per minute

Jan walked at a rate of 3 miles in 30 minutes.

Thus Jan's walking rate = 3/30 = 0.10 miles per minute

So Jan walks faster than Peter Difference = 0.10 - 0.08 = 0.02 miles per minute

So Peter walks slower than Jan at a rate of 0.02 miles per minute. ← option d.

Answer 5

D.

to find the rate at which they were walking is distance/time so
4/50 is .08 for peter and 3/30 is .1 for jan and then you subtract .1 and .08 and you get .02 so jan was walking at a rate of .02 faster than peter

Answer 6

Jan's rate was .1 mile per min
Peter's rate was .08 miles per minute
.1-.08 = .02
answer is d. peter's walking rate was 0.02 mile per minute slower than Jan's.

Answer 7

rate = distance/time

Jan's rate = 3 miles/30 minutes
=1miles/10minutes
=0.10
Peter's rate = 4 miles / 50 minutes
=2miles/25minutes
=0.08

Jan R - Peter R = 0.10 - 0.08
=0.02
Therefore Jan walks 0.02 mile/minute faster than peter.
The answer is D.

Answer 8

d. beacause peter walked at a rate of .08 miles per minute and jan walked.1 miles per minute.

Answer 9

Tianna.... here is the answer:

pete is 4miles/50 min = .08 miles/min
jan is 3miles/30min=.10miles/min

The correct choice is d pete is .02 miles/min slower than Jan

tf

Answer 10

d