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7 answers

SLG is total bases per at-bats.

Formula:

SLG == (hits + doubles + 2*triples + 3*homers) / AB

Approximate, qualitative continuum of SLG:

.200 -- pitcher
.300 -- backup, good-glove shortstop
.350 -- starting, good-glove shortstop
.400 -- catcher, "tough out" second baseman
.450 -- league average
.500 -- slugging first baseman / corner outfielder
.550 -- All-Star
.600 -- MVP
.650 -- possible future Hall Of Famer, second MVP season
.700 -- likely future HOFer
.750 -- HOFer at peak
.800+ -- Ruth/Bonds at peak

2007-05-28 12:25:27 · answer #1 · answered by Chipmaker Authentic 7 · 0 0

SLG = (1B + (2 x 2B) + (3 x 3B) + (4 x HR))/ AB
Slugging average is nearly always referred to as slugging percentage. However, this term is misleading for it is actually a weighted average not a percentage. A decent SLG% would have to be .400

2007-05-28 19:15:11 · answer #2 · answered by Josh P 2 · 0 1

SLG = total bases / AB

A decent SLG depends on your own definition of decent.

THe links below give you more information on stats of all kinds, among other things.

2007-05-28 19:16:16 · answer #3 · answered by Anonymous · 0 0

its the percentage of extra base hits you got out of your hits. like doubles, triples and homeruns. 400 or higher is a really good slugging percentage.

2007-05-28 19:18:06 · answer #4 · answered by Higgy 1 · 0 0

slugging is how many times out of ten you actually put the ball in play with a hit. unlike batting average which is how many times out of ten you get a hit and get on base. a good slugging average would be about .600

2007-05-28 19:14:27 · answer #5 · answered by skater_dominion 2 · 0 3

Sluggin % is defined as a players total number of bases divided by his/her plate appearances. This statistic includes ALL bases, including BB, IBB, HBP, as well as actually hits.

(BB+IBB+HBP+1B+2(2B)+3(3B)+4(HR))/(AB+BB+IBB+HBP+S.Fly + S. Bunt)

2007-05-28 20:16:19 · answer #6 · answered by Dan G 2 · 0 1

the percentage of hits that are extra-base hits. .700 or so. doubles or better.

2007-05-31 18:51:55 · answer #7 · answered by Anonymous · 0 0

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