How does the electric force between two charges change when the distance between them is doubled?
How does it change when the distance is halved?
2007-05-28 10:07:29 · 3 answers · asked by Anderson W 1 in Science & Mathematics ➔ Physics
This is an inverse square law.
F=k Q1Q2/R^2 where
F- force between charges
Q1 and Q2 - charges
k- constant
R- distance between the charges.
a) R=2r then f=(1/4)F
a) R=0.5r then f=4F
2007-05-28 10:11:34 · answer #1 · answered by Edward 7 · 1⤊ 0⤋
The electric force goes as the inverse of the square of the distance. So if it is twice as far apart the distance ratio is 2. The square of 2 is 4. The inverse of 4 is 1/4. So the force is one quarter as much.
2007-05-28 10:12:23 · answer #2 · answered by Brian J 6 · 0⤊ 0⤋
"The magnitude of the electrostatic force between two point charges is directly proportional to the magnitudes of each charge and inversely proportional to the square of the distance between the charges."
2007-05-28 10:12:32 · answer #3 · answered by Thundre 4 · 0⤊ 0⤋