whats the vertex of this equation y= 2x to the second power?

Question

sorry the equatin was y=2x to the second power-6x-8

Answer 1

if you want to do the question without using calculus, which you may or may not know, do this. find out what the values for x are that would make y = 0. then use the value that is directly between them. for this problem, you can factor it down to y = 2(X + 1)(X-4)... therefore, you know that when x = 4, and when x = -1, y will equal zero. so you've got a distance of 5 between those two points and so you use 1.5, the middle point between them, as the X coordinate. then just plug that number into the problem. 2(1.5)(1.5) - 6(1.5) - 8 = y = -12.5, so the answer is (1.5,-12.5)

Answer 2

the vertex of an equation y = ax^2 +bx + c is as follows

x= -b/2a and then you plug this value to get y and you have your coordinate (x,y)

your y = 2x^2 the vertex is at (0,0)

Answer 3

Vertex? Do you mean minimum point?

y = 2x^2 - 6x - 8
dy/dx = 4x - 6
This is zero when x = 1.5, y = -12.5

The minimum is at (1.5, -12.5)

Answer 4

y = 2x^2
The vertex is the origin (0,0)

Answer 5

1.5,-12.5