Parabola with vertex at (0,0) and focus at (3,0)?

Answer 1

We call the vertex (h, k) and we say that it is distance p from the focus. p is positive since the vertex is towards the left of the focus. Then h = 0, k = 0, and p = 3. For a horizontal axis of symmetry, the equation is (y - k)^2 = 4p(x - h). In this case, (y - 0)^2 = 4*3*(x - 0) ==> y^2 = 12x ==> x = (1/12)y^2.

Answer 2

Are you wanting the equation? If so, then c = 3 and the parabola points to the right.

x - 0 = 1/12(y - 0)^2 or leave out the zeros if you prefer