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What is the second derivative of ((3)/(x^(2)-1)) using the quotient rule to solve for the answer? Please show all your work and give an explanation for each step, explaining why each variable and number was placed where it is. I can get to the first derivative with ease, but the second derivative is making my head spin!!! PLEASE HELP!!!

2007-05-28 07:55:12 · 1 answers · asked by Anonymous in Science & Mathematics Mathematics

1 answers

y = 3/(x^2-1)
y' = -3(2x)/(x^2-1)^2 = -6x/(x^2-1)^2
y" = [-6(x^2-1)^2 +6x(2)(x^2-1)(2x)]/(x^2-1)^4
y" = [-6+12x^2]/(x^2-1)^3

2007-05-28 08:08:25 · answer #1 · answered by ironduke8159 7 · 0 0

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