Solving Logarithmic Equations using the Properties of Logarithms
2007-05-28 07:43:10 · 6 answers · asked by Monte S 1 in Science & Mathematics ➔ Mathematics
I'll presume you mean
log base y of 6 = 5.
that means y^5 = 6
So, y = 6^(1/5)
Using logs to solve it...
log(y^5)=log(6). . . log(a^b)=(b)log(a)
(5)log(y)=log(6)
log(y) = log(6)/5
y=antilog(log(6)/5)
2007-05-28 07:54:25 · answer #1 · answered by gugliamo00 7 · 0⤊ 0⤋
Assume in solution that log means log base y:-
log 6 = 5
y^5 = 6
y = 6^(1/5)
y = 1.431
2007-05-28 14:57:31 · answer #2 · answered by Como 7 · 0⤊ 0⤋
Log of an exponential is the exponent times log of the base. Then divide, then antilog to solve for y.
2007-05-28 14:49:06 · answer #3 · answered by Uncle Al 5 · 0⤊ 0⤋
if ur sposed 2 use properties of logs then i think ur sposed 2 use the One-toOne property-[if b^x=b^y, then x=y] but it doesn't really work for this...i guess the answer could just be y=the fifth root of 6
2007-05-28 15:17:57 · answer #4 · answered by Anonymous · 0⤊ 0⤋
log y 6 = 5
6 logy=5
log y=5/6=0.83333
y=6.81 answer
2007-05-28 14:50:30 · answer #5 · answered by Anonymous · 0⤊ 0⤋
y=exp (-(ln(10)))*exp(5) /6
2007-05-28 14:52:13 · answer #6 · answered by theodore bagwell 2 · 0⤊ 0⤋