what is the probability of getting a 7 card or a 9 card prob.?

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2007-05-28 07:37:14 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

P(7 card) = 4/52 = 1/13
P(9 card) = 4/52 = 1/13
As events are mutually exclusive
P(7card or 9card) = P(7 card) + P(9 card)
= 1/13 + 1/13
= 2/13

2007-05-30 21:56:03 · answer #1 · answered by bharat m 3 · 0⤊ 0⤋

Asumming 52 cards
p( 7 card )=4/52=1/13
p(9 card )= 4/52=1/13

2007-05-28 14:42:35 · answer #2 · answered by harry m 6 · 0⤊ 0⤋

There are 4 sevens and 4 nines
Prob (seven or nine) = 8 / 52 = 2 / 13
Prob (seven) = 4 / 52 = 1 / 13
Prob (nine) = 4 / 52 = 1 / 13

2007-05-28 15:04:32 · answer #3 · answered by Como 7 · 0⤊ 0⤋