The length of a rectangle is three times its width. If the area of the rectangle is 192 in^2 find the perimeter
2007-05-28 07:16:57 · 9 answers · asked by angel l 1 in Science & Mathematics ➔ Mathematics
a=lxw for a rectangles area
l=3w so
area=3wxw
so area =3w^2
192=3x^2
divide both sides by 3
64=x^2
x=sqrt(64)
x=8
so the width is 8 and the length is 3x8 or 24
so the perimeter is 2x24+2x8
so 48+16
so 64in
2007-05-28 07:19:38 · answer #1 · answered by Anonymous · 0⤊ 1⤋
suppose the width is w so the length is 3w
The area is 3w*w= 192 or w^2 =64 so the width is 8 in
the length is 3*8=24in
And the perimeter p =2w+2l = 16+32= 48in
2007-05-28 14:21:47 · answer #2 · answered by maussy 7 · 0⤊ 0⤋
l=3x
area =lw=3x^2=192, so x^2=64 and x=8. Therefore, the length is 24 and the width is 8--the perimeter would then be 64.
2007-05-28 14:21:01 · answer #3 · answered by bruinfan 7 · 0⤊ 0⤋
length = l
width = b
l=3b
l*b=192 => 3b*b=192
3b^2 =192
b^2 = 64=> b=8 =>l=24
P = 2*(l+b)= 2*(8+24) =64
2007-05-28 14:21:11 · answer #4 · answered by lil' 2 · 0⤊ 0⤋
area = length times width, so...
3x * x = 192
3x^2 = 192
x^2 = 64
x = 8
so, the sides are 8 and 24 inches, making the perimeter 64 inches.
2007-05-28 14:20:43 · answer #5 · answered by jbone907 4 · 0⤊ 0⤋
Length is 8, Width is 24. What level math are you in?
2007-05-28 14:21:30 · answer #6 · answered by Anonymous · 0⤊ 1⤋
let width=w
let length=3w
a=192^2
w*3w=192
4w=192
4/4 cancels out.
192/4=48
w=48
___w___
| | 3*48=144
| | L=144
3w | w=48
| | 48*2=96
|_______| 144*144=288
288+96=384
p=384
2007-05-28 14:27:04 · answer #7 · answered by Elyse 1 · 0⤊ 0⤋
3N X N = 192
N^2 = 64
N = 8
P = 2 X ( 3N + N) = 8 N
P = 64
Keep Smilin'
2007-05-28 14:29:20 · answer #8 · answered by HANAN. 3 · 0⤊ 0⤋
Just ask your math teacher!!!I hate math!
2007-05-28 14:20:28 · answer #9 · answered by Kay 2 · 0⤊ 1⤋