A ballon which is in the form of a perfect sphere , is being filled with water . After containing one litre wa

Question

A ballon which is in the form of a perfect sphere , is being filled with water . After containing one litre water, its radius is ‘x’,then how much water should be added to make its radius double?
"give calculation process"

Answer 1

V=4/3*pi*r^3
I
f the Volume is 1 litre, the radius is x, so,

1=4/3*pi*x^3
If you substitute x with 2x, you get,
V=4/3*pi*(2x)^3
=4/3*pi*8x^3

So Volume should be 8 Litres.

So you need to add 7 more litres of water.

Answer 2

When you double the dimensions of a 3-dimensional object you increase its volume by 8 times. The balloon would have 8 litres of water in it -- so you would have to add 7. Sorry, I didn't calculate this, I just knew.

Answer 3

The formation of the earth is not directly related to the Big Bang. The earth was formed by an aggregation of dust and gas, and current scientific theory is that after it formed it was impacted by a large body that resulted in the earth/moon pair. It's not perfectly spherical, and in fact this is what cause the length of the day to shorten by 1 1/4 milliseconds after the last major earthquake; it threw it off-balance in a new way.

Answer 4

V is proportional to r^3

So doubling the radius means increasing the volume 8 fold.
So the new volume should be 8 litres, hence 7 litres should be added.

Aren't you proud of me for using the British spelling of litre.

Answer 5

Since the volume of a sphere is 4pir^3/3 by doubling the raius you would have to increase the volume by factor(2)^3=8; therefore, you would have to add 7 more liters to accomplish this task.

Answer 6

Algorithm:
1.Volume of the sphere=4/3*3.14*radius^3=1 lit
2.r=cubic root of 3/(4*3.14)
3.2*r=2*cubic root of 3/(4*3.14)=1.240 lit

Basically 1 unit of radius will give 0.6204 units of Volume

Answer 7

v=4/3*pi*x^3=1 L
v'=4/3*pi*(2x)^3
v'-v=4/3*22/7*x^3[8-1]=28/3*22/7*x^3=88/3*x^3
=4/3*pi*x^3*7=7v=7*1=7 liters will double up the radii

Answer 8

ofcourse 1 ltr more coz if radius is x in one ltr then to double the radius v require the same as v pour the water b4..

Answer 9

V = (4/3) . pi . r^3
V/2 = (4/6) . pi . r^3
if V/2 = 1 Lt, then
(4/6) . pi . r^3 = 1 Lt
r^3 = 6Lt/(4 . pi) = 0.48
r = 0.78
when r = 1.56
V/2 = (4/6) . pi . 1.56^3 = 3.27
So 2,27 Lt must be added.

Answer 10

V = (4/3) . pi . r^3
V/2 = (4/6) . pi . r^3
if V/2 = 1 Lt, then
(4/6) . pi . r^3 = 1 Lt
r^3 = 6Lt/(4 . pi) = 0.48
r = 0.78
when r = 1.56
V/2 = (4/6) . pi . 1.56^3 = 3.27
So 2,27 Lt must be added.