A shuffleboard player pushes a 0.25 kg puck, initially at rest, with a horizontal force of 6.00 N moving it through a distance of 0.200 m. Neglect friction.
(a) What is the kinetic energy of the puck when the force is removed?
_____ J
(b) What is the speed of the puck when the force is removed?
_____ m/s
2007-05-28 07:14:03 · 2 answers · asked by Khoi 1 in Science & Mathematics ➔ Physics
WORK-ENERGY THEOREM
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2007-05-28 07:15:00 · update #1
a = F/m = 6/.25 = 24 m/s^2
t = (2x/a)^0.5 = (2*0.4/24)^2 = 0.18 sec
v = at = 24 * 0.18 = 4.3 m/s
KE = 1/2mv^2 = 1/2 * 0.25 * 4.3^2 = 2.3 J
(two sig figs)
2007-05-28 07:25:51 · answer #1 · answered by gebobs 6 · 0⤊ 0⤋
that's astonishing they gave you the solutions without explaining them. considering friction isn't present, the flair skill = Kinetic skill. So, the artwork on the p.c.. generates the its kinetic skill, consequently the fee. Thats is the coolest judgment in the back of the 1st answer. yet in any different case to think of, the 6 N stress is the only stress accelerating the p.c.., considering friction is absent. From Newtons, 2d regulation you will discover the acceleration and remedy the equations of kinematics. usually, we use the conservation regulations whilst suitable in classical dynamics.
2016-12-12 04:24:32 · answer #2 · answered by ? 4 · 0⤊ 0⤋