when the distance between two charges is doubled, the electrical force between the charges..
a)increases four times.
b) doubles.
c) halves.
d) is reduced by a 1/4.
2007-05-28 04:19:12 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Physics
c -- for a given "point" charge, the force has equipotential lines at every distance "r" away from it. However, this force is spread out over the area, which is "4*pi*r^2" -- making it weaker as you move further away. Hence the force decreases with (1/ (4*pi*r^2). In a comparison of the two states, the "4*pi" cancels out mathematically.
2007-05-28 04:54:10 · answer #1 · answered by Hooligan 2 · 0⤊ 0⤋
d. is reduced by a 1/4 is the correct answer. The electrical force is inversely proportional to the square of the distance. So, if distance doubles, the force becomes 1/4th.
2007-05-28 04:39:32 · answer #2 · answered by Swamy 7 · 0⤊ 0⤋
The electrical force is reduced by a factor of 4, it is not reduced by 1/4.
inverse square law, the charge is divided by 4, or 1/4 of the original
2007-05-28 04:29:59 · answer #3 · answered by science teacher 7 · 0⤊ 0⤋
The relationship is an inverse square law ie F is proportional to 1/r^2
Hence if r doubles, then F decreases by a factor of 4
2007-05-28 04:25:36 · answer #4 · answered by dudara 4 · 1⤊ 0⤋
option c)
2007-05-28 04:26:59 · answer #5 · answered by student of honorZ 2 · 0⤊ 1⤋