trigonometry!!?

Question

if cscx > 0 and secx < 0, then angle x is in what quadrant??

i still don't get it, how is it in quadrant 1 or 2? =)

Answer 1

if cscx > 0 then sinx > 0 ie +ve
is secx < 0, cosx < 0 ie -ve

Using the acronym ASTC.
Both sin and cos are +ve in the first quadrant
sin is +ve and cos is -ve in the second, and that's the one we want.

Answer 2

It's in the second quadrant.

All trigonometric functions are positive, > 0, when angle "x" is in the first quadrant, so if secx < 0, then x WILL NEVER BE in the first quadrant.

Therefore, if cscx = 1 / sinx > 0, and secx = 1 / cosx <0, then x is in the second quadrant.

Remember that only sinx and cscx are positive in the second quadrant.

Hope it helps

Answer 3

cscx > 0 in first and second quadrant
secx < 0 in second and third quadrant

then x in the second quadrant

Answer 4

csc = 1/sin and sec = 1/cos. Therefore, csc has the same sign as sin and sec has the same sign as cos. sin is positive in quadrants I and II and cos is negative in quadrants II and III. So with a positive sin and negative cos, we'd be in the second quadrant, quadrant II.

Answer 5

The x has to be in the first quadrant, almost impossible for it to be in the second, would not work out.

Answer 6

u know 'ASTC' rule if don't know then look
the following
in 1st qudrant all are +ve
in 2nd quadrant s for 'sin' is +ve that means cosec is also +ve
in 3rd quadrant t fro 'tan' is +ve
in fourthquadrant c for 'cos' is +ve
so from above
u can get that only in
2nd quadrant cosec is +ve
and sec is -ve

Answer 7

Angle x is in the first quadrant.