2007-05-27 20:21:08 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Gervald ^^^ is incorrect.
This reaction proceeds to form a HALOHYDRIN. You first form the bromonium ion. Then the water attacks the most substituted carbon (one with the most carbocation character) while the bromine steals an electron pair from the same carbon. Then a proton is lost. The final product is called 3-bromo-2-methyl-2-butanol.
And yeah, one of your carbons does have too many bonds.
2007-05-27 21:58:56 · answer #1 · answered by Rick P. 3 · 0⤊ 1⤋
You seem to have written the formula incorrectly.
Put 1 x Br on each C atom at each end of the double bond, and convert the double bond into a single bond.
Eg CH3CHBrCBr(CH3)2
A second product is also possible, as a side-reaction, replacing the right-hand -Br with an -OH group.
2007-05-27 20:46:02 · answer #2 · answered by Gervald F 7 · 0⤊ 1⤋