Start with pythagoras' theorem
opp^2 + adj^2 = hyp^2
Divide throughout by hyp^2 to get
sin^2 + cos^2 = 1
2007-05-27 18:04:26
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answer #1
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answered by Dr D 7
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Draw a circle of radius 1. Let P be a point on the circle and O the origin. the angle OP makes with positive x axis, call it a.
The co-ordinates of P are (cos a, sin a). Now use the pythogorean theorem.
hypotenuse ^2 = x^2 + y ^ 2 = cos^2 a + sin ^ a.
but we have a unit circle, so hypotenuse = 1
substitute and get the desired result.
2007-05-27 18:04:18
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answer #2
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answered by Anonymous
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Use a theoretical right angle triangle of length x, height y and hypotenuse h.
Now we know that a^2 + b^2 = c^2
therefore x^2 + y^2 = h^2
now x = h cos(theta)
y = h sin(theta)
h^2 cos^2(theta) + h^2 sin^2(theta) = h^2
divide by h^2
cos^2(theta) + sin^2(theta) = 1
and thus proved!!
2007-05-27 18:26:05
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answer #3
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answered by theanswerman 3
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Pythagorean Theorem.
That is just how sin and cosine are defined. Use the unit circle.
2007-05-27 18:01:41
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answer #4
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answered by Aadi C 2
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Consider cos à and sin à where:-
cos à = x / r
sin à = y / r
cos² à + sin² à = x² / r² + y² / r²
cos² à + sin² à = (x² + y²) / r² = r² / r² = 1
2007-05-28 02:52:39
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answer #5
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answered by Como 7
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