A Rhombus has sides of length 10 and its diagonals differ by 4. What is its area?
2007-05-27 17:53:03 · 4 answers · asked by firedragonof2005 1 in Education & Reference ➔ Homework Help
Answer 1 ? Shoot the writer of the book! I don't want my kids to learn from teachers who read and believe books like that.
Answer 2 could be correct.
When you draw a rhombus you end up with four right angled triangles which are congruent. With one side(the hypotnuse) being 10 units the other sides must be 6 and 8 units, respectively. (pythagorian triads). Base X height / 2 gives size of one. times four gives area of rhombus.
2007-05-27 19:19:12 · answer #1 · answered by jemhasb 7 · 0⤊ 0⤋
Area of a rhombus=1/2*(1st diagonal)*(2nd diagonal)
So you may need to find the lengths of the diagonals. However I did the calculations but I am really sorry that I can't give it to you.
I found that diagonal 1=12, and diagonal 2=(12+4)=16
So Area=1/2*12*16=96 square units.
2007-05-27 18:37:08 · answer #2 · answered by Aparna P 2 · 0⤊ 0⤋
Neat question. Draw the rhombus and its diagonals. They form 4 right triangles. Call the length of one half-diagonal x. That makes the length of the other half-diagonal x+2. Now by the pythagorean theorem, x^2 + (x+2)^2=100. This has two solutions-- x=-8 and x=6. Toss -8. Now each of the four triangles has sides of length 6, 8, and 10. The area of each is 6*8*.5= 24, so the total area is 96.
2016-05-19 05:53:07 · answer #3 · answered by sandy 3 · 0⤊ 0⤋
Well, a rhombus is just a slanted square. How do you find the area of a square? Length x's height. The diagonals have nothing to do with it. It should be 100 units squared. right?
2007-05-27 18:03:18 · answer #4 · answered by Deanne A 1 · 0⤊ 0⤋