square root of 3x/2
please explain this to me because I am not getting it.
Thanx
2007-05-27 16:46:22 · 2 answers · asked by Jamie 2 in Education & Reference ➔ Homework Help
Take the square root of the numerator and denominator separately, and then simplify the entire fraction by rationalizing the denominator. Here's what I mean:
√(3x/2) = √3x / √2.
Now, since we don't ordinarily leave a radical in the denominator of a fraction, we rationalize it by multiplying both the numerator and denominator by the denominator. That gets rid of square roots in the denominator of the fraction.
(√3x / √2)(√2 / √2) = (√3x)(√2) / (√2)² = √[(3)(2) x] / 2 = √6 x / 2.
We read the final result as the square root of 6 times x divided by 2.
2007-05-27 16:50:09 · answer #1 · answered by MathBioMajor 7 · 2⤊ 0⤋
(sq rt 3x) / (sq rt 2)
((sq rt 3x)*(sq rt 2)) / 2
2007-05-28 00:44:41 · answer #2 · answered by doug_johnson39 2 · 0⤊ 0⤋