Did I do this problem correctly ?

Question

1/6 – 1/3t > 0

-1/3t> -1/6

Divide each side by -1/3 – multiply by the reciprocal
t= (-1/6) ( -3/1)

t= 3/6
t= 1/2

Answer 1

This is correct:
-1/3 t > -1/6
Multiply out by 3:
-t > -1/2
Multiply out by -1:
t < 1/3 note how the direction changed
t never reaches 1/3, but is less than it

Answer 2

No, starting with an inequality, your answer must be an inequality

1/6-1/3 t>0 subtract 1/6 frrm each side (you did this)
-1/3 t>-1/6 multiply both sides bt -3 AND FLIP THE INEQUALITY SIGN

T<1/2

Answer 3

remember that this is an inequality and towards the end you got rid of the greater than sign.

1/6 - 1/3t > 0
-1/3t > -1/6, mult by 3
-t > -1/2 , mult by -1. you must reverse the greater than sign to become less than

t < 1/2

Answer 4

1/6 > 1/3t
t> 6/3 = 2
t>2

Answer 5

Close

1/3 of 1/2 = 1/6 - you have that much correct.

However you forgot your sign - and your inequality symbol.

t < -1/2

So you have a negative * negative = positive, and;
increasingly small 't' so you are moving away (staying
greater than) zero.

Answer 6

you did it wrong! here is how you do it.
-1/3 t > -1/6
Multiply out by 3:
-t > -1/2
Multiply out by -1:
t < 1/3

Answer 7

wrong. t< 1/2. when doing an inequality, change the direction of the sign when dividing by a negative number.

Answer 8

i dont think so ... but i got what u did until the t= (-1/6) (-3/1) ... wouldnt it t=(-1/6) (-1/3) ? .... but if this is algibra i got a D in the class so dont be mad if im wrong ok ...

Answer 9

I hope you realize you switched from a '>' to a '='. There is a dramatic difference.