Which of the ordered pairs
(–11, 3), (1, 0), (–7, –2), (–19, 5)
2007-05-27 16:25:49 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The ones that are solutions are:
(-11,3)
(1,0)
(-19,5)
2007-05-27 16:29:13 · answer #1 · answered by coltsfan65418 2 · 0⤊ 0⤋
x + 4y = 1
(-11, 3)
-11+4*3=1
-11+12=1
1=1 IS a solution
x + 4y = 1
(1, 0)
1+4*0=1
1=1 IS a solution
x + 4y = 1
(-7, -2)
-7+2(-2)=1
-7-4=1
-11â 1 is not a solution
x + 4y = 1
(-19, 5)
-19+4*5=1
-19+20=1
1=1 Is a solution
(-11, 3); (1, 0) & (-19, 5) are all solutions
(-7, -2) is not a solution.
2007-05-27 23:41:45 · answer #2 · answered by yupchagee 7 · 0⤊ 0⤋
All of them except (-7,-2) satisfy the equation.
(-11)+(4)(3)=1
(-11)+12=1-- Correct
(1)+(4)(0)=1
1+0=1---Correct
(-7)+(4)(-2)=1
(-7)+(-8)=(-15) not 1---Incorrect
(-19)+(4)(5)=1
(-19)+20=1---Correct
2007-05-27 23:33:39 · answer #3 · answered by Jake 2 · 0⤊ 0⤋
Substitute the ordered pairs into the equation and see if it works., The answer is the last one -19 +20 = 1.
To get fancy, you could graph the line x +4y=1. The ordered pairs are just points. Then you look to see which points the line intersects.
2007-05-27 23:31:20 · answer #4 · answered by squeezie_1999 7 · 0⤊ 0⤋
all except (-7,-2) are correct
2007-05-27 23:30:00 · answer #5 · answered by miatasan1 2 · 0⤊ 0⤋