How many mililiters of 18.4 M H2SO4 are needed to prepare 600.0mL of 0.10 M H2SO4?

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How many mililiters of 18.4 M H2SO4 are needed to prepare 600.0mL of 0.10 M H2SO4?

2007-05-27 14:58:03 · 2 answers · asked by neas182000 1 in Science & Mathematics ➔ Chemistry

2 answers

Very simple formula

M1V1 = M2V2

M = molarity
V = volume (mL is fine)

You have 3 of the 4 pieces. Just plug in and solve for V2.

2007-05-27 15:05:44 · answer #1 · answered by reb1240 7 · 0⤊ 0⤋

Let the final sulfuric acid solution be called S. Let the 18.4M solution be called s.

600.0mLS x 0.10molH2SO4/1000mLS x 1000mLs/18.4molH2SO4 = (600.0)(0.10)(1000)/(1000)(18.4) = 3.261mLs

2007-05-27 15:08:35 · answer #2 · answered by steve_geo1 7 · 0⤊ 0⤋