Calculate the molarity, molality & mole fraction of a 35.5% salt solution?

Question

This is all I know what do i do!!?

Answer 1

35.5% is a mass percent.

So you have 35.5 g of NaCl in 1000 g of water

The molality is easy. Convert the 35.5 grams to moles and divide by 1 kg.

The molarity is 35.5 grams plus 1000 grams of water. Take the moles of salt and divide by 1.035 for the molarity

Finally mole fraction. You already have the moles of salt. Now take the 1000 gr of water and covert that to moles. Add the 2 moles together for the total. Now you can calculate the mole fraction of each component against the total moles

Answer 2

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Calculate the molarity, molality & mole fraction of a 35.5% salt solution?
This is all I know what do i do!!?

Answer 3

Let the solution be called S.
Atomic weights: Na=23 Cl=35.5 NaCl=58.5

Molarity:
35.5gNaCl/100mLS x 1molNaCl/58.5gNaCl x 1000mLS/1LS = 6.07M

Molality:
35.5gNaCl/64.5gH2O x 1molNaCl/58.5gNaCl x 1000gH2O/1kgH2O = (35.5)(1000)/(64.5)(58.5) = 9.41molNaCl/1kgH2O

Mole fraction:
1000gH2O x 1molH2O/18gH2O = 55.6molH2O
(9.41molNaCl)/(9.41molNaCl + 55.6molH2O) = 0.144