2007-05-27 14:47:50 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
well let's set the age of the son is x, which would led the dad would be 7x.....
sum of their age is 56, mean 7x +x = 56.....8x=56.....x=7
son is 7 years old, and the dad is 49 years old
hope this help
2007-05-27 14:51:57 · answer #1 · answered by Mrs. Jenny 2 · 0⤊ 0⤋
the son's age, assume it to be x
if the father age is 7 times of his son the the father's age is assumed to be 7x if their ages add up to 56 then it would be:
7x+x=56
8x=56
x=56\8
x=7
if the father is 7 times is old as his son then his age is :7*7=49 so the son's age is :56-49=7
so the father's age is 49 and the son's age is 7(since 49+7=56)
2007-05-27 21:59:27 · answer #2 · answered by Dr. Eddie 6 · 0⤊ 0⤋
son=x
father=7x
sum of their ages=x+7x=56
8x=56
x=56/8
x=7
son=7
father=7x7=49
2007-05-27 21:56:07 · answer #3 · answered by sam 3 · 0⤊ 1⤋
if f=father and s=son
from the problem, we can deduce that
f=7s and s+f=56
s=56-f
f=7(56-f)
f=392-7f add 7f to both sides
8f=392 divide by 8
f=49 plug into s=56-f
s=7
2007-05-27 21:53:59 · answer #4 · answered by Jen 3 · 0⤊ 1⤋
let son be x years of age
father is 7x
7x + x = 56
8x = 56
x = 7
Son is 7 years of age
Father is 49 years of age.
2007-05-28 02:45:19 · answer #5 · answered by Como 7 · 0⤊ 0⤋
7x + x = 56
8x = 56
x= 7
Father 49
Son 7
2007-05-27 21:55:41 · answer #6 · answered by Kate 3 · 0⤊ 1⤋