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2007-05-27 10:54:47 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

6 answers

Nikki:

sqrt(50x^2) = sqrt(50)*sqrt(x^2)
= sqrt(25)*sqrt(2)*x
= 5x*sqrt(2)

Good luck!

2007-05-27 10:59:29 · answer #1 · answered by alrivera_1 4 · 0 1

Easy. Stop using the √ symbol and start thinking about the square root as what it is, an exponent of 1/2.

√(50x^2) is really (50x^2)^(1/2)

There as a rule about exponents
(ab)^p = (a^p)(b^p)

So
(50x^2)^(1/2) = [50^(1/2)][(x^2)^(1/2)]
={[25^(1/2)] [2^(1/2)]} {x^[(2)(1/2)]}
because of the rule already mentioned, and also because of a rule that says (n^p)^q = n^(pq)

We know that 25^(1/2) = 5 (or -5). We also know that x^[(2)(1/2)]=x^1 and x^1 = x (or -x)

So we have
(50x^2)^(1/2) = [50^(1/2)][(x^2)^(1/2)]
={[25^(1/2)] [2^(1/2)]} {x^[(2)(1/2)]} =
(5)(x)[2^(1/2)] but we don't know if it's positive or negative.

2007-05-27 18:17:45 · answer #2 · answered by gugliamo00 7 · 0 1

√(50x^2)
= √(2*5^2*x^2)
= 5|x|√2
------------
You have to use the absolute sign for x. Otherwise, it is not right. For example, if x = -1, √(50x^2) = 5√2. But 5x√2 = -5√2.

2007-05-27 18:00:13 · answer #3 · answered by sahsjing 7 · 0 0

since this is the same as asking for the square root of
5^2 x^2
the answer would be 5|x|
the absolute value sign is necessary in case x is negative

2007-05-27 18:01:52 · answer #4 · answered by Concetta Z 2 · 0 1

50 x^2= 25 x^2 * 2
sqrt of 25 x^2 *2
5x sqrt 2

2007-05-27 19:44:18 · answer #5 · answered by Dave aka Spider Monkey 7 · 0 1

use a calculater
sq.rt of 50x^2 = 7.0710678118654752440084436210485x

2007-05-27 17:59:53 · answer #6 · answered by pksk212 3 · 0 0

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