Nikki:
sqrt(50x^2) = sqrt(50)*sqrt(x^2)
= sqrt(25)*sqrt(2)*x
= 5x*sqrt(2)
Good luck!
2007-05-27 10:59:29
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answer #1
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answered by alrivera_1 4
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Easy. Stop using the â symbol and start thinking about the square root as what it is, an exponent of 1/2.
â(50x^2) is really (50x^2)^(1/2)
There as a rule about exponents
(ab)^p = (a^p)(b^p)
So
(50x^2)^(1/2) = [50^(1/2)][(x^2)^(1/2)]
={[25^(1/2)] [2^(1/2)]} {x^[(2)(1/2)]}
because of the rule already mentioned, and also because of a rule that says (n^p)^q = n^(pq)
We know that 25^(1/2) = 5 (or -5). We also know that x^[(2)(1/2)]=x^1 and x^1 = x (or -x)
So we have
(50x^2)^(1/2) = [50^(1/2)][(x^2)^(1/2)]
={[25^(1/2)] [2^(1/2)]} {x^[(2)(1/2)]} =
(5)(x)[2^(1/2)] but we don't know if it's positive or negative.
2007-05-27 18:17:45
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answer #2
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answered by gugliamo00 7
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â(50x^2)
= â(2*5^2*x^2)
= 5|x|â2
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You have to use the absolute sign for x. Otherwise, it is not right. For example, if x = -1, â(50x^2) = 5â2. But 5xâ2 = -5â2.
2007-05-27 18:00:13
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answer #3
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answered by sahsjing 7
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since this is the same as asking for the square root of
5^2 x^2
the answer would be 5|x|
the absolute value sign is necessary in case x is negative
2007-05-27 18:01:52
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answer #4
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answered by Concetta Z 2
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50 x^2= 25 x^2 * 2
sqrt of 25 x^2 *2
5x sqrt 2
2007-05-27 19:44:18
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answer #5
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answered by Dave aka Spider Monkey 7
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use a calculater
sq.rt of 50x^2 = 7.0710678118654752440084436210485x
2007-05-27 17:59:53
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answer #6
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answered by pksk212 3
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