I have to make 0.05 M of solution of a substance, i was thinking about using Copper II Acetate, but if you have other easier substances maybe i can use them , I also need a detailed description of how i made the solution, the common and chemical name of the substance and its formula.
2007-05-27 08:25:40 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
If you make 0.05M copper(II) acetate, you will probably use the blue-green monohydrate, Cu(C2H3O2)2*H2O, which is the most common article of commerce. To make 1 L, you will weigh iout 0.05 mole, add it to a 1-L beaker, and dissolve to the 1-L mark with water. Let cupric acetate hydrate be called CA.
Atomic weights: Cu=63.5 C=12 H=1 O=16 Cu(C2H3O)2*H2O=199.5
0.05molCA x 199.5gCA/1molCA = 9.98gCA
For mutliples or fractions of 1 L of solution, multiply the number of L by 9.98.
2007-05-27 08:40:37 · answer #1 · answered by steve_geo1 7 · 1⤊ 0⤋
The formula is (CH3COO)2Cu
molar mass = 181.5 g/mol
0.05 moles weight = 0.05 x 181.5 = 9.08 g
Dissolve 9.08 g of Copper II acetate in enought water to reach 1 L
2007-05-27 08:32:43 · answer #2 · answered by Non più attiva su answers 7 · 0⤊ 1⤋