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1(3)+2(4)+3(5)+4(6)

2007-05-27 08:18:19 · 3 answers · asked by colleen k 1 in Science & Mathematics Mathematics

3 answers

1(3)+2(4)+3(5)+4(6) =
1(1 + 2)+2(2 + 2)+3(3 + 2)+4(4 + 2) =
&Sigma n(n+2), where n goes from 1 to 4

->or n goes from 1 to infinity if we have
"1(3)+2(4)+3(5)+4(6) + ..." instead of
"1(3)+2(4)+3(5)+4(6)"

Hope this helps.

2007-05-27 08:21:01 · answer #1 · answered by M 6 · 7 1

S =Sigma from 1 to n ( n(n+2))

2007-05-27 08:29:10 · answer #2 · answered by ironduke8159 7 · 0 3

Before you write in sigma notation, you have to
find the sequence characteristics, and how they relate to an index. In this case, the coefficients of the term are in a straight arithmetic sequence while the terms in () are also in a straight arithmetic sequence, but offset by +2. So we can summarize
Sum = SIGMA(1 to 4) n(n+2)

2007-05-27 08:25:11 · answer #3 · answered by cattbarf 7 · 1 4

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