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5 answers

Let "S" be sigma:

S 3^(n)

with n running from 0 to infinity

2007-05-27 08:19:07 · answer #1 · answered by kdesky3 2 · 0 0

S = Sigma from 0 to n (3^n)

2007-05-27 15:25:26 · answer #2 · answered by ironduke8159 7 · 0 0

Write the sigma sign in the middle.

5 on the topo the sigma

x=1 on the bottom

on the right side of the sigma, write x to the power of 3

2007-05-27 15:25:12 · answer #3 · answered by Linz 3 · 0 1

&Sigma^∞_n=0 (3^n)

2007-05-27 15:31:31 · answer #4 · answered by Anonymous · 0 0

108
+13
___
121

2007-05-27 16:12:48 · answer #5 · answered by Anonymous 3 · 0 0

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