2007-05-27 08:05:56 · 7 answers · asked by angie_noah06 2 in Science & Mathematics ➔ Mathematics
7x + 3 ≥ 6x + 12
7x + 3 - 6x ≥ 6x + 12 - 6x
x + 3 ≥ 12
x + 3 - 3 ≥ 12 - 3
x ≥ 9
- - - - - - - - -s-
2007-05-27 08:19:54 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
7x + 3 > 6x + 12 can't include the = part!...don't know the key! but pretend it's there, OK?
7x + 3 - 6x > 6x + 12 - 6x sub. 6x from both sides
x + 3 > 12 actually subtracted here
x + 3 - 3 > 12 - 3 sub. 3 from both sides
x > 9
You would color in the 9 (to show the = part) and then color all numbers and the arrow to the right. All the numbers you colored will make the sentence true.
2007-05-27 17:49:35 · answer #2 · answered by Rita L 1 · 0⤊ 0⤋
to solve for x you need to get x all by its self. First subtract 3 from both sides to get 7x>6x+9.
then subtract 6x from both x>9
so the solution it all numbers where x is greater than or equal to 9
2007-05-27 15:15:03 · answer #3 · answered by Bryan A 2 · 0⤊ 0⤋
7x+3>=6x+12
7x-6x+3>=6x-6x+12
x+3-3>=12-3
x>=9
2007-05-27 19:57:26 · answer #4 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
x>_ 9
2007-05-27 15:10:46 · answer #5 · answered by ape 1 · 0⤊ 0⤋
x is greater than or equal to 9
2007-05-27 15:10:59 · answer #6 · answered by dannyman_l 2 · 0⤊ 0⤋
well I think its 9
2007-05-27 16:00:29 · answer #7 · answered by Anonymous 3 · 0⤊ 0⤋