how do u solve it, like to find one of the legs or its hipotenus
and thanx
2007-05-27 08:00:19 · 8 answers · asked by Italyfan 4 in Science & Mathematics ➔ Mathematics
The sides of a triangle are always in the ratio 1:1:(sqrt 2)
2007-05-27 08:07:14 · answer #1 · answered by jimbob 6 · 0⤊ 0⤋
The 45-45-90 triangle is an isosceles right triangle. Therefore if the two legs have the length of a, then the hypotenuse = â2 a. You can use Pythagorean theorem to prove it.
2007-05-27 15:06:27 · answer #2 · answered by sahsjing 7 · 0⤊ 0⤋
label each side with A, B, and C, with A being the horizontal leg of the 90 degree angle, B being the vertical leg making up the 90 degree angle, and C being the hypotenuse (line opposite the 90 degree angle obviously the longest).
To find any side of the triangle, use this equation: A^2+B^2=C^2 and use algebra to find and side:
Examples:
1. find the hypotenuse (C). Using the equation above, to isolate C all by itself, take the square root of of both sides of the eqaution (this will cancel out the C squared leaving it just as C) so that the equation reads C= the square root of (A^2+B^2) but DO NOT cancel out the squares for A and B, this would lead you to a wrong answer. plug in your values for A and B, slove for their squared values, add them, then take the square root of that number to slove for C.
2. To find Leg A or B, once again use A^2+B^2=C^2, Plug in the given values for C and Leg A or B (depending on what Leg is given) find thier squared terms, subtract the Leg from the Hypotenuse (C) and take the square root of that answer to find the missing Leg.
2007-05-27 15:33:19 · answer #3 · answered by calisurfer941 5 · 0⤊ 0⤋
well if it's 45, 45 90 triangle....then the leg across from the 45 is gonna be x and the leg across of the 90 (chance to be hypotenus is high) is gonna be x root 2 which mean x times square root of 2....
hope this help
2007-05-27 15:06:29 · answer #4 · answered by Mrs. Jenny 2 · 0⤊ 0⤋
The sides adjacent to the right angle are equal, call the measure x. The hypotenuse is sqrt(x^2 + x^2) = x*sqrt(2).
2007-05-27 15:03:49 · answer #5 · answered by jcsuperstar714 4 · 0⤊ 0⤋
You need to know the length of only one of the sides. If the side's length is "x" and the hypotenuse length is "y" then 2x^2=y^2 and solve.
2007-05-27 15:04:52 · answer #6 · answered by the_emrod 7 · 0⤊ 0⤋
Let h = hypotenuse and s = one of the two equal legs.
Then h =s*sqrt(2), and
s = hsqrt(2)/2.
This comes up frequently in math so it would be wise to commit it to memory.
2007-05-27 15:12:45 · answer #7 · answered by ironduke8159 7 · 0⤊ 0⤋
use a2+b2=c2 where c is the hypotaneuse and a and b are the legs
2007-05-27 15:04:43 · answer #8 · answered by randy j 1 · 0⤊ 0⤋