Please solve the following maths equation for me:?

Question

x+1=2(1-x)

Note that 2 is under root and not any other number. Please solve in steps if you can. Thank you

Answer 1

Do you mean x + 1 = √2 ( 1 - x) ?

x + 1 = √2 - (√2)x

x + (√2)x = √2 - 1

x(1 + √2 ) = √2 - 1

x = (√2 - 1) / (1 + √2 )

x = (√2 - 1)(1 - √2 ) / (1 + √2 )(1 - √2 )

x = 3 - 2√2

Answer 2

I am reading this as:-
x + 1 = √2.(1- x)
x² + 2x + 1 = 2.(1 - 2x + x²)
x² + 2x + 1 = 2 - 4x + 2x²
0 = x² - 6x + 1
x = [ 6 ± √32 ] / 4
x = [ 6 ± 4√2 ] / 8
x = [ 3 ± 2√2 ] / 4

Answer 3

(x+1)=2(1-x) (assuming under root is the same thing as square root)

then (x+1)=2(1-x)= (x+1)=(1-x)

(x+1)^2=(1-x)

x^2+2x+1=1-x

x^2+3x=0
x(x+3)=0

x=0, -3