i can prove 2=3 bcoz i have a proper method for it. see it & tell me any error is their?

Question

as 2=2
therefore, 2-8=2-8 i.e -6=-6.
: 9-15=4-10 i.e (3)whole sq. -2*5/2*3 = (2)whole sq. -2*5/2*2
adding 25/4 to both side we get,
(3-5/2)whole sq. =(2-5/2)whole sq.
taking underoot on both sides we get,
3-5/2=2-5/2
as 5/2 cancel out in both sides we get,
3=2, hence the final result.

Answer 1

it's right up to

(3 - 5/2)^2 = (2 - 5/2)^2

this expression is trivial, since it simplifies to

(1/2)^2 = (-1/2)^2

when you take square roots of an expression, you need to consider both positive and negative roots.

considering the negative root would give you

3 - 5/2 = 5/2 - 2, or 1/2 = 1/2.

In other words,

a^2 = b^2 does NOT imply a = b. That was your error.



as for yeochief, adding the 25/4 to both sides and simpliflying to squares of differences was a proper step, it was just written in a confusing way. I can see what they were doing... the mistake was the step that assumed that

a^2 = b^2 ====> a = b.

Answer 2

Your proper method didn't even make sense at the very beginning
How can you even get -2*5/2*3= -2*5/2*2?
I don't get what you mean by whole square, but when you square both sides, the answer is different anyway.
So its kind of like saying 2=2
2*4=2*3
Here's my proof 8=6
You might have divided by 0 somewhere along the way or taken the squareoot of a negative, which still should work.

Answer 3

I believe your proof breaks down at the point where you add 25/4 to both sides of the equation.

2*5/2*3 = 15 however 2/2 *5/2*3does not equal 15 it equals 7.5

by converting 2 to a fraction that allows you to create the square 25/4 you have changed 2 to 1

Answer 4

Your math and logic are about as good as is your grammar. Take ESOL before proceeding further in all three.