8^(2/3) algebra help?

Question

can someone please explain how to solve 8 to the power of two thirds?

thanks

Answer 1

8^(2/3)
=[8^2]^(1/3)
=[64]^(1/3)
=[4^3]^(1/3)
=4^(3/3)
=4^1
=4#

Answer 2

8^(2/3) = 2² = 4

Answer 3

8^(2/3) = 4

Answer 4

8^(2/3) = (2^ 3 )^(2/3) = 2^2 = 4 ( 2/3 x 3 = 2 )

Answer 5

hey
i will first explain 8^ (1/2) because its easier:
that equals

squaroot of 8. every squaroot has an imaginary 2 on the top, which is because of the 2 in the fraction and the 1 is 8^1.

so..... 8^(2/3) :

*3squareroot (8^2)
3sqrtroot(64)
this is not 3 times sqrtroot of 64. but what number multiplied by itself 3 times will give you 64. and that number is...4

enjoy.

Answer 6

It means the 3rd root of 8, two times. But I don't think you can do that. I will give you an example 27^(2\3) = the third root of 27, which is 3, two times so, 3 time 3.

Answer 7

The answer is 4. I typed it in my calculator. This really means that 8 is to the third power and that you must take the square root of 3.

Answer 8

8^(2/3)
= (2^3)^(2/3)
= 2^2
= 4

Answer 9

The answer is 4. This how you solve it:
Recall order of operations - (solve exponents first, then division)
1) You take 8^2 ( 8x8) first which gives you 64.
2) Then you take the cube root of 64, which means 64 is a product of the same number to the power of 3.
3) This number is 4 because 4x4x4=64. That's my check!

Now there is your answer!

Answer 10

[(n)^a}^b=n^a*b=n^b*a :

8^2/3={(8)^2}^1/3

Answer 11

its the same thing as taking the cubed root of 8 squared..so 8^2 is 64, the cubed root of that is 4